Triangle ABC is isosceles, E is the point of intersection of the bisectors of the angles at the base.

Triangle ABC is isosceles, E is the point of intersection of the bisectors of the angles at the base. The AEC angle is 150 degrees. Find the interior corners of a triangle

Since the triangle ABC is isosceles, the angle BAC = BCA.

The segments AK and CH are bisectors of equal angles, then the angle KAS = НСA, and then the triangle AOС is also isosceles.

Angle OAC = OAC = (180 – AOC) / 2 = (180 – 150) / 2 = 15.

Then the angle BAC = BCA = 2 * 15 = 30.

The sum of the inner angles of the triangle is 180, then the angle ABC = (180 – 30 – 30) = 120.

Answer: The angles of the triangle ABC are 30, 30, 120.