Triangle ABC is rectangular and isosceles with a right angle C and a hypotenuse of 6 cm.
Triangle ABC is rectangular and isosceles with a right angle C and a hypotenuse of 6 cm. The segment CM is perpendicular to the plane of the triangle and is equal to 5 cm. Find the distance from point M to line AB
To solve the problem, consider the figure.
Consider an isosceles right-angled triangle ABC, in which the angle C is straight, and AB = 6 cm, AC = BC.
Let us find the legs of the triangle ABC by the Pythagorean theorem.
AB ^ 2 = BC ^ 2 + AC ^ 2.
36 = 2 * AC ^ 62.
AC = √18.
Let us draw the CE height to the hypotenuse AB and find its value.
CE = AC * BC / AB = √18 * √18 / 6 = 3 cm.
Consider a right-angled triangle CME and, by the Pythagorean theorem, find the hypotenuse ME.
ME ^ 2 = CM ^ 2 + CE ^ 2 = 52 + 32 = 25 + 9 = 34.
ME = √34.
Answer: The distance from M to AB is √34 cm.