Triangle ABC is rectangular, angle C is 90 degrees, CM is median, AB. is 16 cm, angle A is 30 degrees. Find BC and CM.

According to the condition, we are given that the angle A = 30 degrees, the leg lying opposite the angle of 30 degrees is equal to half of the hypotinus (CB) = 8 cm. Since the median creates 2 angles at the base of 90 degrees + 30 degrees (angle A) = 180 degrees – 120 degrees = 60 degrees (angle of UTC) +90 degrees at base = 120 degrees. 180 degrees – 120 degrees = 60 degrees (angle B), then (AC) is equal to 2 times the side (CB) and is equal to 16 centimeters (AC) = 16 See. Consider the AFM triangle. The CM side lies opposite an angle of 30 degrees and is equal to half of the hypotinose (AC) AND CM = 8 centimeters.
Answer: CM = 8cm, CB = 8cm.