Since the segment CH is the height of the triangle ABC, then the triangle ACN and BCH are rectangular.
The sum of the acute angles of a right-angled triangle is 90, then the angle ACH = (90 – CAH) = (90 – 52) = 38.
Angle ACB = 90, then angle BCH = (90 – ACH) = (90 – 38) = 52, angle СBН = 90 – 52 = 38.
Answer: Angle 1 = 3 = 38, angle 2 is 52.
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