Triangle ABC is rectangular with right angle C, height CH is height, angle A = 52 degrees, find angle 1, 2, 3

Since the segment CH is the height of the triangle ABC, then the triangle ACN and BCH are rectangular.

The sum of the acute angles of a right-angled triangle is 90, then the angle ACH = (90 – CAH) = (90 – 52) = 38.

Angle ACB = 90, then angle BCH = (90 – ACH) = (90 – 38) = 52, angle СBН = 90 – 52 = 38.

Answer: Angle 1 = 3 = 38, angle 2 is 52.