Triangle ABC – isosceles (AB = BC), BD – bisector. CBD = 70º. What are the angles of the triangle ABD.

In the problem statement, an isosceles triangle ABC is given. A bisector BD is drawn from the vertex B, which formed the angle CBD equal to the angle ABD. In an isosceles triangle, the bisector is also the height of this triangle, which means it has formed a right angle ADB, which is 90 degrees. Since the sum of all three angles of the triangle is 180 degrees, and in triangle ABD, the angle ABD = 70 degrees and the angle ADB is 90 degrees, find the angle BAD.
180-70-90 = 20 degrees.
Answer: In triangle ABD, angle A is 20 degrees, angle B is 70 degrees, angle D is 90 degrees.