Triangle ABC-isosceles AC = 7 cm-base P of triangle = 27 cm find the sides of the triangle

Triangle ABC-isosceles AC = 7 cm-base P of triangle = 27 cm find the sides of the triangle and and the middle line is parallel to the base.

If triangle ABC is isosceles and side AC is base, then sides AB and BC are equal.

The perimeter is the sum of all sides, which means P = AC + AB + BC, but since we have AB = BC, the formula can be changed in this way P = AC + 2AB.
Replace with numbers.
27 = 7 + 2AB
2AB = 27 – 7
2AB = 20
AB = 20/2
AB = 10 and from this it follows that BC = 10, mk AB = BC.
By the theorem, the middle line is equal to half of the side to which it is parallel.
Wed line = AC / 2 = 7/2 = 3.5 cm.
Answer: AB = 10 cm, BC = 10 cm, cf. line = 3.5 cm.