Triangle ABC side BC = AC = 6.3 and angle C = 54 degrees. Find side AB and other angles.
| June 19, 2021 | education
By the cosine theorem, we find the side AB:
AB = √ (BC² + AC² – 2 * BC * AC * cos C) ≈ 5.72 units.
Equal sides of the triangle lie opposite equal angles, therefore BC = AC, it follows that the angles B and A are equal to each other.
Because the sum of the angles of the triangle is 180 °, then the angle B = A = (180 ° – 54 °) / 2 = 63 °.
Answer: AB ≈ 5.72 units, A = B = 63 °.
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