# Triangle MPK-isosceles with base MP, straight line AB is parallel to KP. A belongs to MK, B belongs

**Triangle MPK-isosceles with base MP, straight line AB is parallel to KP. A belongs to MK, B belongs to MP, find the angle MAB and ABm if the angle K = 72 degrees. and the angle M = 54 degrees**

Triangle MKP, by condition, isosceles, then the angle of the MPC, at the base of the MP, is equal to the angle of the MPC. KPM angle = 54.

Let us prove that triangles MKP and MAB are similar.

The angle M in triangles is common, the angle MAB is equal to the angle KPM, as are the corresponding angles at the intersection of parallel lines KP and AB secant MP. Then the triangle MKP and MAB are similar in two angles.

In such triangles, the corresponding angles are equal, then the angle MAB = MKP = 72, the angle ABM = KPM = 54.

Answer: The MAB angle is 72, the ABM angle is 54.