Triangles ABC and DBC are isosceles with base BC, it is known that AB = CD. prove that these triangles are equal.

Since triangles ABC and DCB are isosceles, AB = AC, CD = BD.

By condition, AB = CD, then AB = AC = CD = BD.

The side BC of the triangles is common, then the triangles ABC and DBC are equal on three sides, which was required to be proved.



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