Triangles are known to be similar and their areas are 49/64. How do their perimeters relate?

According to the theorem on the areas of similar triangles: the ratio of the areas of similar triangles is equal to the square of the similarity coefficient. That is:

S1 / S2 = k² = 49/64

k = 7/8 is the coefficient of similarity.

According to the theorem on the perimeters of similar triangles: the ratio of the perimeters of such triangles is equal to the coefficient of similarity, that is:

P1 / P2 = k = 7/8.

Answer. P1 / P2 = 7/8.



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