Trivalent metal bromide contains 89.88% bromine. Determine the atomic mass of metal.

Route M is an unknown trivalent metal, and MBr3 is its bromide.

Find the molecular weight of the trivalent metal bromide:

M (MBr3) = M (Br3) * 100 / w (Br3) = 240 * 100 / 89.88 = 267 (amu).

Let’s find the atomic mass of a trivalent metal:

M (M) = M (MBr3) – M (Br3) = 267 – 240 = 27 (amu), which corresponds to the metal aluminum (Al).

Answer: 27 amu



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