Two 10 ohm and 5 ohm resistance bulbs are connected in parallel. Find the amperage in the second light if the voltage is 120V.

Answer: 36 A.
Explanation of the solution to the problem: to solve this problem, you must use the following formula:
R (total) = R1 * R2 / (R1 + R2), where R (total) is the total resistance of the resistors connected in parallel, R1 and R2 are the resistances of the two resistors.
Substituting the values known from the condition of the problem into the formula, we obtain:
R (total) = 10 * 5 / (10 + 5) = 3.33 (Ohm).
Next, you need to find the current strength by the formula:
I = U / R (total), where I is the current in the circuit, U is the voltage in the DC circuit.
We substitute:
I = 120 / 3.33 = 36 A.

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