Two alloys of which the first contains 35% nickel and the second contains 60% nickel

Two alloys of which the first contains 35% nickel and the second contains 60% nickel, then they were alloyed with each other and received 210 kg of an alloy containing 40% nickel, how many kg is the mass of 1 alloy.

Let x be the mass of the first alloy. Since the result is an alloy with a mass of 210 kg, the mass of the second alloy is (210 – x) kg.

In the first alloy, 35% nickel, which means pure nickel in this alloy is 0.35x.

In the second alloy 60% nickel, pure nickel in it 0.6 (210 – x).

In the resulting alloy 40: nickel, that is, 40% of 210 kg.

0.4 * 210 = 84 (kg) – pure nickel.

The equation turns out:

0.35x + 0.6 (210 – x) = 84.

0.35 + 126 – 0.6x = 84.

-0.25x = -42.

x = 42: 0.25 = 42 * 4 = 168 (kg) – the mass of the first alloy.



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