Two balls are given. The radius of the first is 6 times the radius of the second. How many times is the surface area

Two balls are given. The radius of the first is 6 times the radius of the second. How many times is the surface area of the first ball greater than the surface area of the second?

The surface area of the ball is found by the formula:

S = 4 * pi * r ^ 2, where S is the area, pi is a mathematical constant equal to 3.14, r is the radius of the ball.

The surface area of the second ball, if we take its radius as r, is equal to:

4 * pi * r ^ 2.

Then the surface area of the first ball, the radius of which is 6 times the radius of the second, is equal to:

4 * pi * (6r) ^ 2 = 4 * 36 * pi * r ^ 2.

If we compare the two values obtained, we find that the surface area of the first ball is 6 times the surface area of the second ball.

Answer: 6 times.