Two balls, lead and iron, of equal mass are suspended from the balance beam.

Two balls, lead and iron, of equal mass are suspended from the balance beam. Will the balance of the balance be upset if the balls are immersed in water?

Dmw = mzhel.
ρw = 11300 kg / m ^ 3.
ρzhel = 7800 kg / m ^ 3.
Let’s find the volumes of these balls: Vw = mw / ρw, Vzhel = mzw / ρzw. Since mw = md and ρw> rd, then Vw <Vd.
When immersed in water, the buoyancy force of Archimedes, directed vertically upwards, will act on the balls.
The buoyancy force of Archimedes is determined by the formula: Farch = ρ * g * V. Where ρ is the density of the liquid in which the body is immersed, g is the acceleration of gravity, V is the volume of the immersed part of the body in the liquid.
Since Vsw <Vzhel, the buoyant force that acts on the ball of lead Farkh (sun) will be less than the buoyancy force that acts on the ball of iron Farkh (ch).
Answer: will pull the lead ball.