Two balls of the same mass rolls uniformly on the table, the speed of the first ball is 1m / s

Two balls of the same mass rolls uniformly on the table, the speed of the first ball is 1m / s, the speed of the second is 2.5m / s, the impulse of which ball is greater and how many times?

The solution of the problem:

From the condition we know that m1 = m2 = m.

To find the momentum, you need to use the formula: p = m * v.

p is the impulse;

m is the mass;

v is the speed.

1) p1 = 1 * m = m;

2) p2 = 2.5 * m.

Since the masses are the same, the momentum of the second is greater than the momentum of the first, i.e. p2> p1 or 2.5 * m> m.

p2 / p1 = (2.5 * m) / m = 2.5.

Answer: The impulse of the second is greater than the impulse of the first; the impulse of the second is 2.5 times greater than the impulse of the first.




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