Two balls, one with a mass of 200 g and the other with a mass of 250 after the collision, flew in different directions.

Two balls, one with a mass of 200 g and the other with a mass of 250 after the collision, flew in different directions. a ball of less mass as a result of a collision acquired a speed of 5 m / s. What is the distance that a ball of greater mass travels in 2 seconds? Consider that the speed of the ball will not change during this time.

Given:

m1 = 200 grams = 0.2 kilograms – the mass of the first ball;

m2 = 250 grams = 0.25 kilograms – the mass of the second ball;

v1 = 5 m / s – speed of the first ball after collision.

t = 2 seconds – time span.

It is required to determine the distance S (meters) that the second ball flew in time t.

Find the speed of the second ball after collision:

m1 * v1 = m2 * v2;

v2 = m1 * v1 / m2 = 0.2 * 5 / 0.25 = 4 m / s.

Then, the path traversed by the second ball will be equal to:

S = v2 * t = 4 * 2 = 8 meters.

Answer: a ball with a greater mass will fly a distance of 8 meters.