Two bars with the same mass, m 0.2 kg, were placed on an inclined plane with an inclination angle of 45 (degrees)

Two bars with the same mass, m 0.2 kg, were placed on an inclined plane with an inclination angle of 45 (degrees). The coefficient of friction of the upper bar on the plane is 0.01, of the lower one. Find the force of interaction of the bars when they slip together

To find the forces with which the bars act on each other, you need to determine all the forces that act on each bar separately, add them up and write them down in the form of Newton’s second law.
The gravity component mg acts on each bar along the x-axis:
Px = mg * cos45 °.
The reaction of the plane N to the gravity of the bars in absolute value is equal to the component Py:
= = mg * cos45 °.

Answer: 0.69 N.