Two bodies are simultaneously thrown down from one point with different speeds V2 and V1.

Two bodies are simultaneously thrown down from one point with different speeds V2 and V1. How will the bodies move relative to each other?

If the counting is carried out from a height from which two bodies are thrown, then the equations of their uniformly accelerated downward motion will be written as
H1 = V1 * t + g * (t ^ 2) / 2,
H2 = V2 * t + g * (t ^ 2) / 2;
The position of the bodies relative to each other changes according to the formula:
H2 – H1 = (V2 – V1) * t;
The second body is evenly removed from the first.