Two bodies move uniformly in mutually perpendicular directions with speeds of 3

Two bodies move uniformly in mutually perpendicular directions with speeds of 3 and 4 m / s. Their speed relative to each other is equal.

Given:

v1 = 3 m / s;

v2 = 4 m / s.

Find the relative velocity v.

Since both bodies move perpendicularly, we find their relative speed from the Pythagorean formula for a right-angled triangle:

v = √ (v1 ^ 2 + v2 ^ 2) = √ (9 + 16) = √ (25) = 5 m / s.

Answer: the relative speed of the bodies is 5 m / s.