Two bodies of the same volume are completely immersed in water. When the bodies were released, the first drowned

Two bodies of the same volume are completely immersed in water. When the bodies were released, the first drowned, and the second began to float. Compare the forces of Archimedes acting on these bodies.

A buoyant force equal to the weight of the displaced fluid acts on a body immersed in a liquid, and is called the Archimedes force:
Fа = ρ * g * V, where ρ is the density of the fluid, g is the acceleration of gravity of a body raised above the Earth g = 9.8 m / s², V is the volume of the body.
If we have both bodies of the same volume, then the force of Archimedes acts on them the same.
Fа1 = ρ * g * V
Fа2 = ρ * g * V
Fа1 / Fа2 = ρ * g * V / ρ * g * V = 1
Being in the water, weight and buoyancy force acts on it, if the weight is greater, then the body will sink, if it is less buoyant, it will float. It turns out that the weight of the first body is greater than the weight of the second.
Answer: the forces of Archimedes are equal.