Two bodies weighing 400 and 600 g. moved towards each other and stopped after the impact.

Two bodies weighing 400 and 600 g. moved towards each other and stopped after the impact. What is the speed of the second body if the first was moving at a speed of 3 m / s?

Given:
m1 = 400 g = 0.4 kg
m2 = 600 = 0.6 kg
V1 = 3 m / s
Find: V2 -? m / s
Decision :
p before = p after – Z.S. And
m1 * V1-m2 * V2 = 0 – (because bodies move towards each other).
m1 * V1 = m2 * V2
V2 = m1 * V1 / m2
[V2] = kg * m / s / kg = m / s.
V2 = 0.4 * 3 / 0.6 = 1.2 \ 0.6 = 2 (m / s).
Answer: 2 m / s.