Two bodies were thrown vertically upward at a speed of 29.4 m / s with a time interval of 0.5 s.

Two bodies were thrown vertically upward at a speed of 29.4 m / s with a time interval of 0.5 s. How long after the moment the first body is thrown and at what height will they meet?

Because two bodies are thrown at the same speed and at different times, while the second is flying up, the first will already begin to fall
The maximum height would be:
H = V ^ 2 / 2g = 43.2 m
Because the rise and fall times are the same, then they will meet when the first body falls 0.25s
h = H-g * 0.25 ^ 2/2 = H-0.3 = 42.9m