Two buses left at the same time towards each other from points M and N, the distance between which is 70 km
Two buses left at the same time towards each other from points M and N, the distance between which is 70 km, and after 40 minutes simultaneously arrived at the intermediate point P. Find the distance between points M and P, if it is known that the average speed of the bus leaving point M , turned out to be 15 km / h more than the average speed of the bus leaving point N.
We will solve this problem using the equation.
1. Let us denote by x the speed of the bus leaving point N.
2. Find the speed of the bus leaving point M.
x + 15 km / h.
3. Determine how many kilometers the bus that left N. traveled in 40 minutes.
x km / h * 40 min = x km / h * 2/3 h = 2/3 x km.
4. Find the distance the bus traveled from point M.
(x + 15) km / h * 40 min = (x + 15) km / h * 2/3 h = 2/3 x + 10 km.
5. Let’s compose and solve the equation.
2/3 x + 2/3 x + 10 = 70;
4/3 x = 60;
x = 45.
6. The speed of the bus leaving N is x = 45 km / h.
7. The speed of the bus leaving M is 45 km / h + 15 km / h = 60 km / h.
8. Find the distance between M and P.
60 km / h * 40 min = 60 km / h * 2/3 h = 40 km.
Answer: The distance between M and P is 40 km.