Two cars are moving towards each other at speeds of 18 km / h and 54 km / h, the distance between

Two cars are moving towards each other at speeds of 18 km / h and 54 km / h, the distance between them is 600 m. In how many seconds they will meet

V1 = 18 km / h = 5 m / s.

V2 = 54 km / h = 15 m / s.

S = 600 m.

tvs -?

With uniform rectilinear movement, the path passed by the first S1 and the second S2 car will be expressed by the formula: S1 = V1 * t, S2 = V2 * t, where V1, V2 is the speed of the cars, t is the time of movement.

Since the cars met while driving, they together traveled the distance S: S = S1 + S2.

S = V1 * tvs + V2 * tvs = (V1 + V2) * tvs.

tвс = S / (V1 + V2).

tvs = 600 m / (5 m / s + 15 m / s) = 30 s.

Answer: cars will meet in time tвs = 30 s.



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