Two cars are moving towards each other on a horizontal highway at speeds of 6m / s and 4m / s. The weights of the cars are the same and equal to 103 kg. Determine the kinetic energy of the first car in the frame of reference associated with the second car
1) In the frame of reference associated with the second car, the first car will have a speed v = 6 m / s + 4 m / s = 10 m / s.
2) Then you can calculate its kinetic energy by the formula E = mv2 / 2. Substitute numerical values into it: E = (103 kg) * (10 m / s) 2/2 = 5150 J = 5.15 kJ.
ANSWER: E = 5.15 kJ.
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