Two cars drove out of points A and B towards each other. The speed of the first car is 80 km / h ^ 2, and the second is 10 km / h

Two cars drove out of points A and B towards each other. The speed of the first car is 80 km / h ^ 2, and the second is 10 km / h ^ 2 less than the first. What is the distance between points A and B if the meeting of cars occurs in 2 hours?

Given: v1 = 80 km / h v2 = v1-10 km / h => v2 = 70 km / h t = 2h
S -?
Decision:
S = S1 + S2 because the distance between points is equal to the distance traveled by two cars. S1 = v1 * t S2 = v2 * t Substitute in the general formula and take t outside the brackets. Therefore: S = (v1 + v2) t = (80 + 70) * 2 = 150km / h * 2h = 300km
Answer: 300km