Two cars leave two cities at the same time towards each other. The speed of one of them is 56 km / h

Two cars leave two cities at the same time towards each other. The speed of one of them is 56 km / h, which is 7/8 of the speed of the second. What will be the distance between cars in 2.6 hours after the start of movement, if it is known that the distance between cities 410 km?

Let’s find the speed of the second car:

x * 7/8 = 56;

x = 56 * 8/7 = 64 km / h;

Let’s find the distance that each of the cars has traveled:

56 * 2.6 = 145.6 km;

64 * 2.6 = 166.4 km;

Let’s calculate the distance between the cars 2.6 hours after the start of the movement:

410 – 145.6 – 166.4 = 98 km.

Answer: the distance between cars is 98 km.