Two charges 60 μC and – 20 μC are located at a distance of 0.4 m from each other. Determine the field strength

| August 22, 2021 | education

Two charges 60 μC and – 20 μC are located at a distance of 0.4 m from each other. Determine the field strength at a point located in the middle of a straight line segment connecting the charges.

Point charge system tension:
E = E1 + E2, where E1, E2 are the intensity of point charges.
Е1 = k * | q1 | / r ^ 2, k – coeff. proportionality (k = 9 * 10 ^ 9 N * m ^ 2 / Cl ^ 2), q1 is a point charge (q1 = 60 μC = 60 * 10 ^ -6 C), r is the distance from a point charge (r = 0, 4/2 = 0.2 m).
E2 = k * | q1 | / r ^ 2, q2 is a point charge (q2 = – 20 μC = – 20 * 10 ^ -6 C).
E = k * | q1 | / r ^ 2 + k * | q2 | / r ^ 2 = k * (| q1 | + | q2 |) / r ^ 2 = (9 * 10 ^ 9) * (60 * 10 ^ -6 + 20 * 10 ^ -6) / 0.2 ^ 2 = 18 * 10 ^ 6 V / m.
Answer: The field strength is 18 * 10 ^ 6 V / m.



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