Two charges located at a certain distance act on each other in a vacuum with a force of 10 ^ -4 N
| February 4, 2021 | education
Two charges located at a certain distance act on each other in a vacuum with a force of 10 ^ -4 N, and in a liquid with a force of 5 * 10 ^ -5 N. Find the relative permeability in a liquid
These tasks: Fв (the force with which two charges taken interact in vacuum) = 10-4 N; Fzh (force of interaction of charges in the considered liquid) = 5 * 10-5 N.
The relative dielectric constant of the liquid in question is determined by the formula: ε = Fw / Fzh.
Calculation: ε = 10-4 / (5 * 10-5) = 2.
Answer: The relative dielectric constant of the liquid in question is 2.
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