Two chords AB and CD are drawn in the circle, intersecting at the point K, KC = 6 cm

Two chords AB and CD are drawn in the circle, intersecting at the point K, KC = 6 cm, AK = 8 cm, BK + DK = 28 cm. Find the product of BK and DK.

We apply the property of intersecting chords, according to which the product of the lengths of the segments of one chord formed at the intersection is equal to the product of the lengths of the segments of the other chord.

Let the length of the segment BK = X cm, then DK = (28 – X) cm.

DC * CK = AK * ВK.

(28 – X) * 6 = 8 * X.

168 – 6 * X = 8 * X.

14 * X = 168.

X = BK = 168/14 = 12 cm.

DK = 28 – 12 = 16 cm.

Then ВK * DK = 12 * 16 = 192.

Answer: The product of the segments is 192.



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