Two conductors connected in parallel have a resistance of 2.4 ohms. The resistance of one of these conductors

Two conductors connected in parallel have a resistance of 2.4 ohms. The resistance of one of these conductors is 6 ohms. Find the resistance of the circuit when connecting these conductors in series.

Let the resistance of the first conductor R1 = 6 ohms, R2 – the desired resistance of the second conductor.

Since the conductors are connected in parallel, the total resistance of the circuit is:

R = R1 * R2 / (R1 + R2) = 2.4 Om.

6 * R2 = 2.4 * (6 + R2).

6 * R2 – 2.4 * R2 = 2.4 * 6.

3.6 * R2 = 14.4.

R2 = 14.4 / 3.6 = 4 Om.

Then, when the conductors are connected in series, the resistance of the circuit will be equal to:

R = R1 + R2 = 6 + 4 = 10 Om.

Answer: The resistance of the circuit is 10 ohms.