Two conductors of the same length and of the same material are connected in series. The diameter of the first conductor is 1 mm

Two conductors of the same length and of the same material are connected in series. The diameter of the first conductor is 1 mm, the second is 2 mm. The system has a voltage of 300 V. Determine the voltage on the second conductor.

Given:
d1 = 1 mm;
d2 = 2 mm;
L1 = L2;
U = 300 B.
Find: U2.
Decision:
In order to find the radius, we will use this formula. It must be found, since it is a mandatory variable in the formula for finding the voltage.
Let’s write the formula:
R1 = пo * L / S1 = 4 * пo * L / (n * d1 ^ 2)
The situation is similar with the second radius.
R2 = пo * L / S2 = 4 * пo * L / (n * d2 ^ 2).
From this we get:
R1 / R2 = d2 ^ 2 / d1 ^ 2 = 4.
Next, we find the current strength:
I = U1 / R1 = U2 / R2.
Let’s make a proportion
U1 / U2 = R1 / R2 = 4
U1 = U-U2
Let’s find the voltage.
U2 = U / 5 = 300/5 = 60 V
Answer: 60