Two conductors with a resistance of 10 ohms 25 ohms are connected in parallel and connected to a network

| April 28, 2021 | education

Two conductors with a resistance of 10 ohms 25 ohms are connected in parallel and connected to a network with a voltage of 100v, determine the total resistance of the section, the current strength on each conductor and the total current in the circuit.

Given:

R1 = 10 Ohm – resistance of the first conductor;

R2 = 25 Ohm – resistance of the second conductor;

U = 100 Volts – electrical circuit voltage.

It is required to determine R (Ohm) – the total resistance of the circuit, I1, I2 (Ampere) – the current on each conductor and I (Ampere) – the total current.

Since the conductors are connected in parallel, the total resistance will be:

R = R1 * R2 / (R1 + R2) = 10 * 25 / (10 + 25) = 250/35 = 7.1 ohms (the result has been rounded to one decimal place).

The current on the first conductor is:

I1 = U / R1 = 100/10 = 10 Amps.

The current on the second conductor is:

I2 = U / R2 = 100/25 = 4 Amps.

The total amperage is equal to:

I = I1 + I2 = 10 + 4 = 14 Amps.

Answer: the total resistance of the circuit is 7.1 ohms, the current on the first conductor is 10 amperes, on the second conductor is 4 amperes, the total current in the circuit is 14 amperes.



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