Two conductors with a resistance of 10 ohms and 30 ohms are connected in parallel, in a circuit with a voltage of 12 V.
Two conductors with a resistance of 10 ohms and 30 ohms are connected in parallel, in a circuit with a voltage of 12 V. Find the current in each conductor, the total current, the total resistance of the circuit.
Given:
r1 = 10 Ohm – resistance of the first conductor;
r2 = 30 Ohm – resistance of the second conductor;
U = 12 Volts – electrical circuit voltage.
It is required to determine I1, I2 (Ampere) – the current on the conductors r1 and r2, I (Ampere) – the total current and Rtot (Ohm) – the total resistance of the electrical circuit.
On the first conductor, the current is:
I1 = U / r1 = 12/10 = 1.2 Amperes.
On the second conductor, the current strength is:
I2 = U / r2 = 12/30 = 0.4 Ampere.
The total amperage is equal to:
I = I1 + I2 = 1.2 + 0.4 = 1.6 Amps.
Since the conductors are connected in parallel, the total resistance will be:
R = r1 * r2 / (r1 + r2) = 10 * 30 / (10 + 30) = 300/40 = 7.5 ohms.
Answer: the current at r1 is 1.2 amperes, at r2 it is 0.4 amperes, the total current in the circuit is 1.6 amperes, the total resistance of the circuit is 7.5 ohms.
