Two conductors with a resistance of 5 ohms and 10 ohms are connected in parallel to the battery.

| June 22, 2021 | education

Two conductors with a resistance of 5 ohms and 10 ohms are connected in parallel to the battery. The current strength in which of them is greater and how many times? Find the total resistance of the circuit.

When the conductors are connected in parallel, the voltage at their terminals will be the same.

U1 = U2 = U.

Determine the strength of the current passing through the section of the circuit with a resistance of 5 ohms.

I1 = U / R1 = U / 5 A.

Determine the strength of the current passing through the section of the circuit with a resistance of 10 ohms.

I2 = U / R2 = U / 10 A.

Then I1 / I2 = (U / 5) / (U / 10) = 2.

Determine the total resistance of the circuit.

Since the conductors are connected in parallel, then R = R1 * R2 / (R1 + R2) = 5 * 10/15 = 10/3 = 3 (1/3) ohms.

Answer: On the first conductor, the force is 2 times greater, the resistance of the circuit is 3 (1/3) Ohm.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.