Two conductors with a resistance of 5 ohms and 12 are connected in parallel and connected to a source of electrical energy.

| January 5, 2021 | education

Two conductors with a resistance of 5 ohms and 12 are connected in parallel and connected to a source of electrical energy. In the first, 420J of heat was released in 10 seconds. What amount of heat will be released in the second conductor in 1 minute?

R1 = 5 ohms.
R2 = 12 ohms.
Q1 = 420 J.
t1 = 10 s.
t2 = 1 min = 60 s.
Q2 -?
According to the Joule-Lenz law, the amount of thermal energy Q that is released in a conductor with a current is expressed by the formula: Q = U ^ 2 * t / R, where U is the voltage at the ends of the conductor, t is the time of passage of the electric current, R is the resistance of the conductor …
Q1 = U1 ^ 2 * t1 / R1.
Q2 = U2 ^ 2 * t2 / R2.
With parallel connection of conductors, the voltage at their ends is the same: U1 = U2.
U1 ^ 2 = Q1 * R1 / t1.
Q2 = Q1 * R1 * t2 / R2 * t1.
Q2 = 420 J * 5 Ohm * 60 s / 12 Ohm * 10 s = 1050 J.
Answer: Q2 = 1050 J of thermal energy was released in the second conductor.



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