Two conductors with a resistance of 6 ohms and 10 ohms are connected in series.
Two conductors with a resistance of 6 ohms and 10 ohms are connected in series. What amount of heat will be released in each conductor in 2 minutes if the voltage on the second conductor is 20V.
Given:
R1 = 6 Ohm – resistance of the first conductor;
R2 = 10 Ohm – resistance of the second conductor;
t = 2 minutes = 120 seconds – time span;
U2 = 20 Volts – voltage at the ends of the second conductor.
It is required to determine Q (Joule) – how much heat will be released on the first conductor over a period of time t.
Since both conductors are connected in series, the same current flows through them, which is equal to:
I = U2 / R2 = 20/10 = 2 Amps.
Then the amount of heat will be equal to:
Q = W * t = U1 * I * t = R1 * I * I * t =
= R1 * I2 * t = 6 * 22 * 120 = 6 * 4 * 120 = 2880 Joules.
Answer: in the first conductor in 2 minutes heat will be released, equal to 2880 Joules.