Two conductors with a resistance of 6 ohms and 10 ohms are connected in series.

Two conductors with a resistance of 6 ohms and 10 ohms are connected in series. What amount of heat will be released in each conductor in 2 minutes if the voltage on the second conductor is 20V.

Given:

R1 = 6 Ohm – resistance of the first conductor;

R2 = 10 Ohm – resistance of the second conductor;

t = 2 minutes = 120 seconds – time span;

U2 = 20 Volts – voltage at the ends of the second conductor.

It is required to determine Q (Joule) – how much heat will be released on the first conductor over a period of time t.

Since both conductors are connected in series, the same current flows through them, which is equal to:

I = U2 / R2 = 20/10 = 2 Amps.

Then the amount of heat will be equal to:

Q = W * t = U1 * I * t = R1 * I * I * t =

= R1 * I2 * t = 6 * 22 * ​​120 = 6 * 4 * 120 = 2880 Joules.

Answer: in the first conductor in 2 minutes heat will be released, equal to 2880 Joules.



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