Two cones are given. The base radius and height of the first cone are 6 and 4, respectively, and the second -12 and 3.

Two cones are given. The base radius and height of the first cone are 6 and 4, respectively, and the second -12 and 3. How many times is the volume of the second cone greater than the volume of the first?

The formula for finding the volume of a cone: V = 1/3 * ПR²h (R – base radius, h – height).

Let’s calculate the volume of the first cone: R = 6, h = 4. V1 = 1/3 * п * 6² * 4 = 1/3 *п * 144.

Let’s calculate the volume of the second cone: R = 12, h = 3. V2 = 1/3 * п * 12² * 3 = 1/3 * п * 144 * 3.

Find the ratio of the volumes of the cones:

V2 / V1 = (1/3 * п * 144 * 3) / (1/3 * п * 144) = 3.

Answer: the volume of the second cone is three times larger.