Two containers contain some water. If 25% of the amount of water contained in it is poured from the first container

Two containers contain some water. If 25% of the amount of water contained in it is poured from the first container into the second, then in the second container there will be twice as much water as in the first. If you pour from the second container into the first 11 liters of water, then the first will have three times more water than the second container. How much water is in each container?

Let there be liters of water in the first container A, and liters of water in the second container B. Let’s compose a system of equations:
(A – A * 25/100) * 2 = B + A * 25/100;
(B – 11) * 2 = A + 11;
From the second equation, we express the value of A:
A = (B – 11) * 2 – 11;
And substitute this value into the first expression:
(2 * B – 22 – 11) * 150/100 = B + (2 * B – 22 – 11) * 25/100;
(2 * B – 33) * 3/2 = B + (2 * B – 33) * 1/4;
3 * B – 99/2 = B + B / 2 – 33/4;
(3 – 1 – 1/2) * B = 99/2 – 33/4;
(3 – 1 – 1/2) * B = 99/2 – 33/4;
3/2 * B = (198 – 33) / 4;
B = 165/4: 3/2 = 165/4 * 2/3 = 27.5;
A = (27.5 – 11) * 2 – 11 = 22;
Answer: in the first container 22 liters, in the second container 27.5 liters.