Two cubes weighing 1 kg and 3 kg slide towards each other at a speed of 3 m / s and 2 m / s, respectively.

| November 18, 2020 | education

Two cubes weighing 1 kg and 3 kg slide towards each other at a speed of 3 m / s and 2 m / s, respectively. What is the total impulse of the dice after their absolutely inelastic impact?

Let us direct the x-axis along the motion of a cube with a mass of m1 = 1 kg at a speed v1 = 3 m / s.
The sum of the projections of the impulses of the cubes on the x-axis before the impact:
v1m1 – v2m2 = 3 m / s * 1 kg – 2 m / s * 3 kg = – 3 kg * m / s.
According to the law of conservation of momentum, the momentum of the cubes before impact is equal to the momentum of the cubes after the impact.
The minus sign indicates that the stuck together cubes will move in the direction in which the cube weighing 3 kg moved before impact.
In absolute value, the total impulse after impact is p = 3 kg * m / s.
Answer: In absolute value, the total impulse after impact is p = 3 kg * m / s.



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