Two cyclists are going towards each other on the highway. Now there are 2 km 700 m between them. In 6 minutes they will meet.

Two cyclists are going towards each other on the highway. Now there are 2 km 700 m between them. In 6 minutes they will meet. Find the speed of these cyclists if the speed of the first is 50 m / min higher than the speed of the second.

1km = 1000m
2km700m = 2700m

solve in x
let x (m / min) be the speed of the second cyclist
(х + 50) m / min – speed of the first cyclist
(x + (x + 50)) * 6 = 2700
(x + x + 50) * 6 = 2700
(2x + 50) * 6 = 2700
12x + 300 = 2700
12x = 2700-300
12x = 2400
x = 2400: 12
x = 200

200 (m / min) – speed of the second cyclist
1) 200 + 50 = 250 (m / min) – speed of the first cyclist
Answer: 250m / min speed of the 1st, 200m / min speed of the 2nd.