Two cyclists are moving along a straight track at the initial moment of time, the distance between them was 120 m

Two cyclists are moving along a straight track at the initial moment of time, the distance between them was 120 m. The speed module of the first cyclist is 5m / s and that of the overtaking cyclist is 7m / s how long it will take for the first cyclist to catch up with the second.

S = 120 m.

V1 = 5 m / s.

V2 = 7 m / s.

td -?

Since cyclists move uniformly in a straight line, the path of each of them S1, S2 will be the product of the speed of movement and the time of movement: S1 = V1 * t1, S2 = V2 * t2.

Since they began their movement at the same time, their movement time before the meeting will be the same: t1 = t2 = td.

We express the path of the second cyclist S2 by the formula: S2 = S + S1.

V2 * td = S + V1 * td.

td = S / (V2 – V1).

td = 120 m / (7 m / s – 5 m / s) = 60 s.

Answer: the second cyclist will catch up with the first in time t = 60 s.