Two cyclists left at the same time to meet from points A and B, the distance between them is 30 km per hour

univerkov | January 13, 2021 | education

Two cyclists left at the same time to meet from points A and B, the distance between them is 30 km per hour and they met in 1 hour. What is the speed of each cyclist if the speed of one of them is 2 km per hour more than the other.

Since the distance between the two points was 30 km, and the cyclists met after 1 hour, it means that their speed of convergence was:
30/1 = 30 km / h.
We find the sum of their speeds without taking into account the difference.
Since the speed of one was 2 km / h less, we get:
30 – 2 = 28 km / h.
Find the speed of the first cyclist.
Divide the resulting speed value by 2.
28/2 = 14 km / h.
Find the speed of the second cyclist.
14 + 2 = 16 km / h.
Answer: Cyclists’ speeds are 14 km / h and 16 km / h.

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