Two cyclists left two settlements, located at a distance of 42 km from each other, and moved evenly towards each

Two cyclists left two settlements, located at a distance of 42 km from each other, and moved evenly towards each other, the speed of the first is 8 km / s, which is equal to the speed of the second cyclist if it is known that they met after 50 minutes

Let’s translate 50 minutes into seconds. 50 minutes = 50 * 60 = 3000 seconds, and 42 km in meters, 42 km = 42000 m.

Let’s determine what distance the first cyclist traveled in 3000 seconds.

S1 = V1 * t = 8 * 3000 = 24000 m.

Let’s determine what distance the second cyclist traveled in 3000 seconds before meeting the first.

S2 = 42000 – 24000 = 16000 m.

Determine the speed of the second cyclist.

V2 = S2 / t = 16000/3000 = 6 m / s.

Answer: The speed of the second cyclist is 6 m / s.