Two cyclists set off at the same time towards each other. The first traveled at a speed of 15 km / h

Two cyclists set off at the same time towards each other. The first traveled at a speed of 15 km / h, and the second traveled 6 km more than the first before the meeting. At what speed did the second cyclist ride if he met the first after 3 hours?

1. It is known that the cyclists met 3 hours after they left. Then during this time the first cyclist, whose speed is 15 km / h, will travel 15 * 3 = 45 km.

2. It is known that the second cyclist traveled 6 km more than the first, which means that he traveled 45 + 6 = 51 km.

3. Knowing the travel time and distance covered by the second cyclist, we calculate his speed.

51: 3 = 17 km / h.

Answer: the second cyclist was traveling at a speed of 17 km / h.



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