Two cyclists set off towards each other from two points, the distance between which is 50 km.

Two cyclists set off towards each other from two points, the distance between which is 50 km. If the first one leaves an hour earlier than the second, then they will meet an hour after the first one leaves. How fast does each cyclist travel?

Let’s read the terms and conditions and think about them. The first cyclist left an hour earlier than the other. The second means stands still and does not move. The first continues to move from one point to another. An hour passes. The second one should start moving. At the same time, a meeting takes place, as stated in the conditions. Consequently, the first cyclist covered 50 km in an hour. Its speed is V = S / T = 50/1 = 50 km / h. The other did not have time to go before the meeting. Its path = 0, as is its speed.
Answer: the speed of cyclists is 50 km / h, 0.



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