Two cyclists started moving at the same time from one point in opposite directions. S1 = 2.4km
| April 28, 2021 | education
Two cyclists started moving at the same time from one point in opposite directions. S1 = 2.4km, t1 = 10min, S2 = 4km, t2 = 10min, Determine the distance of the cyclists through the module t = 50min.
S1 = 2.4 km = 2400 m.
t1 = 10 min = 600 s.
S2 = 4 km = 4000 m.
t2 = 10 min = 600 s.
t = 50 min = 3000 s.
S -?
The distance between cyclists S will be the sum: S = S1 “+ S2”, where S1 “is the path of the first cyclist in time t, S2” is the path of the second cyclist in time t.
S1 “= V1 * t = S1 * t / t1.
S1 “= 2400 m * 3000 s / 600 s = 12000 m.
S2 “= V2 * t = S2 * t / t2.
S2 “= 4000 m * 3000 s / 600 s = 20,000 m.
S = 12,000 m + 20,000 m = 32,000 m = 32 km.
Answer: after a time t = 50 minutes, the distance between the cyclists will be S = 32000 m = 32 km.
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