Two devices with resistance R1 = 10 ohm and R2 = 40 ohm are connected in series in the circuit.

Two devices with resistance R1 = 10 ohm and R2 = 40 ohm are connected in series in the circuit. The voltage on the first of them is 3V. What is the voltage on the second fixture?

With a serial connection, the current in the devices will be the same: I = I1 = I2.

I = U1 / R1, where U1 is the voltage on the first device (U1 = 3 V), R1 is the resistance of the first device (R1 = 10 Ohm).

I = U1 / R1 = 3/10 = 0.3 A.

Voltage on the second device:

U2 = I * R2, where R1 is the resistance of the second device (R2 = 40 Ohm).

U2 = I * R2 = 0.3 * 40 = 12V.

Answer: The voltage on the second device is 12 V.



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