Two drops fall from the tap, one after the other. How does the second drop move in the frame of reference

Two drops fall from the tap, one after the other. How does the second drop move in the frame of reference of the first drop after it is detached from the tap?

We will assume that both drops are absolutely identical: they have the same mass and size. Then the speed of falling of two drops will be the same. After the first drop broke away from the tap and began to fall down, it managed to travel a certain distance S before the second drop also began to fall down. Then they will begin to fall downward at the same speed, and a constant distance S will remain between them. Therefore, in the reporting system associated with the first drop, the second drop will be motionless.
Correct answer: she is motionless.